A consumer advocacy group claims that the mean amount of juice in a 16 ounce bottled drink is not 16 ounces, as stated by the bottler. Determine the conclusion of the hypothesis test assuming that the results of the sampling lead to rejection of the null hypothesis.
A. Conclusion: Support the claim that the mean is equal to 16 ounces.
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B. Conclusion: Support the claim that the mean is greater than 16 ounces.
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C. Conclusion: Support the claim that the mean is not equal to 16 ounces.
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D. Conclusion: Support the claim that the mean is less than 16 ounces.
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Question 4 of 40
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0.0/ 2.5 Points |
A consumer group claims that the mean running time for a certain type of flashlight battery is not the same as the manufacturer’s claims. Determine the null and alternative hypotheses for the test described.
A.H0: µ = Manufacturer’s claims Ha: µ < Manufacturer’s claims
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B.
H0: µ = Manufacturer’s claims Ha: µ ¹Manufacturer’s claims
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C.H0: µ = Manufacturer’s claims Ha: µ > Manufacturer’s claims
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D.H0: µ ¹ Manufacturer’s claims Ha: µ = Manufacturer’s claims
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Question 5 of 40
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0.0/ 2.5 Points |
A researcher claims that the amounts of acetaminophen in a certain brand of cold tablets have a mean different from the 600 mg claimed by the manufacturer. Test this claim at the 0.02 level of significance. The mean acetaminophen content for a random sample of n = 41 tablets is 603.3 mg. Assume that the population standard deviation is 4.9 mg.
A. Since the test statistic is greater than the critical z, there is sufficient evidence to accept the null hypothesis and to support the claim that the mean content of acetaminophen is 600 mg.
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B. Since the test statistic is greater than the critical z, there is sufficient evidence to reject the null hypothesis and to support the claim that the mean content of acetaminophen is not 600 mg.
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C. Since the test statistic is less than the critical z, there is sufficient evidence to reject the null hypothesis and to support the claim that the mean content of acetaminophen is not 600 mg.
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D. Since the test statistic is greater than the critical z, there is insufficient evidence to reject the null hypothesis and to support the claim that the mean content of acetaminophen is not 600 mg.
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Question 6 of 40
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0.0/ 2.5 Points |
In 1990, the average duration of long-distance telephone calls originating in one town was 9.3 minutes. A long-distance telephone company wants to perform a hypothesis test to determine whether the average duration of long-distance phone calls has changed from the 1990 mean of 9.3 minutes. Formulate the null and alternative hypotheses for the study described.
A.Ho: µ = 9.3 minutes H a : µ < 9.3 minutes
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B.Ho: µ = 9.3 minutes H a : µ > 9.3 minutes
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C.Ho: µ = 9.3 minutes H a : µ ¹ 9.3 minutes
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D.Ho: µ ¹ 9.3 minutes H a : µ = 9.3 minutes
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Question 7 of 40
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2.5/ 2.5 Points |
A skeptical paranormal researcher claims that the proportion of Americans that have seen a UFO is less than 1 in every one thousand. State the null hypothesis and the alternative hypothesis for a test of significance.
A.H0: p = 0.001 Ha: p > 0.001
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B.H0: p = 0.001 Ha: p < 0.001
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C.H0: p > 0.001 Ha: p = 0.001
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D.H0: p < 0.001 Ha: p = 0.001
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Question 8 of 40
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0.0/ 2.5 Points |
A study of a brand of “in the shell peanuts” gives the following results:
A significant event at the 0.01 level is a fan getting a bag with how many peanuts?
A. 30 peanuts
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B. 25 or 30 peanuts
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C. 25 or 55 peanuts
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D. 25 peanuts
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Question 9 of 40
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0.0/ 2.5 Points |
A two-tailed test is conducted at the 5% significance level. What is the left tail percentile required to reject the null hypothesis?
A. 97.5%
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B. 5%
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C. 2.5%
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D. 95%
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Question 10 of 40
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0.0/ 2.5 Points |
At one school, the mean amount of time that tenth-graders spend watching television each week is 18.4 hours. The principal introduces a campaign to encourage the students to watch less television. One year later, the principal wants to perform a hypothesis test to determine whether the average amount of time spent watching television per week has decreased.
Formulate the null and alternative hypotheses for the study described.
A.Ho: µ = 18.4 hours H a : µ ¹ 18.4 hours
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B.Ho: µ = 18.4 hours H a : µ < 18.4 hours
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C.Ho: µ ³ 18.4 hours H a : µ < 18.4 hours
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D.Ho: µ = 18.4 hours H a : µ > 18.4 hours
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Question 11 of 40
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0.0/ 2.5 Points |
In 1990, the average duration of long-distance telephone calls originating in one town was 9.4 minutes. A long-distance telephone company wants to perform a hypothesis test to determine whether the average duration of long-distance phone calls has changed from the 1990 mean of 9.4 minutes. The mean duration for a random sample of 50 calls originating in the town was 8.6 minutes. Does the data provide sufficient evidence to conclude that the mean call duration, µ, is different from the 1990 mean of 9.4 minutes? Perform the appropriate hypothesis test using a significance level of 0.01. Assume that = 4.8 minutes.
A. With a z of 1.2 there is sufficient evidence to conclude that the mean value has changed from the 1990 mean of 9.4 minutes.
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B. With a P-value of 0.2302 there is not sufficient evidence to conclude that the mean value is less than the 1990 mean of 9.4 minutes.
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C. With a P-value of 0.2302 there is sufficient evidence to conclude that the mean value is less than the 1990 mean of 9.4 minutes.
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D. With a z of –1.2 there is not sufficient evidence to conclude that the mean value has changed from the 1990 mean of 9.4 minutes.
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Question 12 of 40
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0.0/ 2.5 Points |
In the past, the mean running time for a certain type of flashlight battery has been 8.0 hours. The manufacturer has introduced a change in the production method and wants to perform a hypothesis test to determine whether the mean running time has increased as a result. The hypotheses are:
H0 : µ = 8.0 hours
Ha : µ > 8.0 hours
Explain the meaning of a Type II error.
A. Concluding that µ > 8.0 hours when in fact µ > 8.0 hours
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B. Failing to reject the hypothesis that µ = 8.0 hours when in fact µ >
8.0 hours
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C. Concluding that µ > 8.0 hours
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D. Failing to reject the hypothesis that µ = 8.0 hours when in fact µ = 8.0 hours
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Question 13 of 40
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2.5/ 2.5 Points |
A supplier of DVDs claims that no more than 1% of the DVDs are defective. In a random sample of 600 DVDs, it is found that 3% are defective, but the supplier claims that this is only a sample fluctuation. At the 0.01 level of significance, test the supplier’s claim that no more than 1% are defective.
A. Do not reject the null hypothesis and conclude that there is evidence to support the claim that more than 1% of the DVDs are defective.
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B. Reject the null hypothesis and conclude that there is insufficient evidence to support the claim that more than 1% of the DVDs are defective.
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C. Do not reject the null hypothesis and conclude that there is insufficient evidence to support the claim that more than 1% of the DVDs are defective.
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D. Reject the null hypothesis and conclude that there is sufficient evidence to support the claim that more than 1% of the DVDs are defective.
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Question 14 of 40
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0.0/ 2.5 Points |
A psychologist claims that more than 29 percent of the professional population suffers from problems due to extreme shyness. Assuming that a hypothesis test of the claim has been conducted and that the conclusion is failure to reject the null hypothesis, state the conclusion in non-technical terms.
A. There is sufficient evidence to support the claim that the true proportion is less than 29 percent.
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B. There is not sufficient evidence to support the claim that the true proportion is greater than 29 percent.
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C. There is sufficient evidence to support the claim that the true proportion is equal to 29 percent.
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D. There is sufficient evidence to support the claim that the true proportion is greater than 29 percent.
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Question 15 of 40
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0.0/ 2.5 Points |
A long-distance telephone company claims that the mean duration of long-distance telephone calls originating in one town was greater than 9.4 minutes, which is the average for the state. Determine the conclusion of the hypothesis test assuming that the results of the sampling do not lead to rejection of the null hypothesis.
A. Conclusion: Support the claim that the mean is less than 9.4 minutes.
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B. Conclusion: Support the claim that the mean is greater than 9.4 minutes.
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C. Conclusion: Support the claim that the mean is equal to 9.4 minutes.
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D. Conclusion: Do not support the claim that the mean is greater than 9.4 minutes.
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Question 16 of 40
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0.0/ 2.5 Points |
The owner of a football team claims that the average attendance at home games is over 3000, and he is therefore justified in moving the team to a city with a larger stadium. Assuming that a hypothesis test of the claim has been conducted and that the conclusion is failure to reject the null hypothesis, state the conclusion in non-technical terms.
A. There is sufficient evidence to support the claim that the mean attendance is greater than 3000.
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B. There is sufficient evidence to support the claim that the mean attendance is equal to 3000.
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C. There is not sufficient evidence to support the claim that the mean attendance is greater than 3000.
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D. There is not sufficient evidence to support the claim that the mean attendance is less than 3000.
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Question 17 of 40
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0.0/ 2.5 Points |
In the past, the mean running time for a certain type of flashlight battery has been 9.8 hours. The manufacturer has introduced a change in the production method and wants to perform a hypothesis test to determine whether the mean running time has increased as a result. The hypotheses are:
H0 : µ = 9.8 hours
Ha : µ > 9.8 hours
Suppose that the results of the sampling lead to rejection of the null hypothesis. Classify that conclusion as a Type I error, a Type II error, or a correct decision, if in fact the mean running time has not increased.
A. Type I error
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B. Type II error
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C. Correct decision
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D. Can not be determined from this information
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Question 18 of 40
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0.0/ 2.5 Points |
If a fan purchased a bag with 30 peanuts, what is the lowest level at which this would be a significant event?
A. 0.05
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B. 0.025
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C. 0.01
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D. It is not significant at any of the levels given
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Question 19 of 40
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2.5/ 2.5 Points |
A manufacturer claims that the mean amount of juice in its 16 ounce bottles is 16.1 ounces. A consumer advocacy group wants to perform a hypothesis test to determine whether the mean amount is actually less than this. The mean volume of juice for a random sample of 70 bottles was 15.94 ounces. Do the data provide sufficient evidence to conclude that the mean amount of juice for all 16-ounce bottles, µ, is less than 16.1 ounces? Perform the appropriate hypothesis test using a significance level of 0.10. Assume that s = 0.9 ounces.
A.The z of – 1.49 provides sufficient evidence to conclude that the mean amount of juice is less than 16.1 oz.
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B.The z of – 1.49 does not provide sufficient evidence to conclude that the mean amount of juice is less than 16.1 oz.
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C.The z of – 0.1778 does not provide sufficient evidence to conclude that the mean amount of juice is less than 16.1 oz.
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D.The z of – 0.1778 provides sufficient evidence to conclude that the mean amount of juice is less than 16.1 oz.
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Question 20 of 40
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0.0/ 2.5 Points |
A consumer advocacy group claims that the mean amount of juice in a 16
ounce bottled drink is not 16 ounces, as stated by the bottler.
Determine the null and alternative hypotheses for the test described.
A.H0: µ = 16 ounces Ha: µ < 16 ounces
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B.H0: µ ¹ 16 ounces Ha: µ = 16 ounces
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C.H0: µ = 16 ounces Ha: µ > 16 ounces
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D.H0: µ = 16 ounces Ha: µ ¹ 16 ounces
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